If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2y^2+y-351=0
a = 2; b = 1; c = -351;
Δ = b2-4ac
Δ = 12-4·2·(-351)
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2809}=53$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-53}{2*2}=\frac{-54}{4} =-13+1/2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+53}{2*2}=\frac{52}{4} =13 $
| -7/w=-5 | | 3z^2+z-140=0 | | x+(x/5)=73 | | X+3=5x11 | | 3x-12=1=9 | | 2x+9=8x-15 | | 8y-6=4y+18 | | y^2-5y+20=34 | | 7+3/y=y–6 | | -(2-a)=+a | | 3(x–1)+2(3-2x)=6(x+4) | | 5/8k=5/6 | | 3(3−x)=12 | | 104x+31x-27x=102 | | 13x+7=130 | | 10=82.5(x/9000)0.54 | | 18+2x=6(−x+5)−44 | | z=6=28 | | (3^5x)(9^2x)=27 | | 3+2x=7-2x | | 5x+1=4×+4 | | 105-w=166 | | 1/3=x-16 | | 34=5w-11 | | 3+2x=7-2x-x | | 35=5w-11 | | q=21+1/2 | | -4u+24=2(u-3) | | ⅓x=x-16 | | (4y+3y3+9)+(2y2=4y-21)= | | 2y+2=-7y+17 | | 10(2x-5)=-9 |